Assertion :For a system of masses at some finite distance,gravitational field can be zero but gravitational potential can not be zero. Reason: Gravitational field is a vector quantity while gravitational potential is a scalar quantity.

Statement-1 is false, statement-2 is true

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Statement-1 is true, statement-2 is false

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Statement-1 is true, statement-2 is true,statement-2 is a correct explanation for statement-1

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Statement-1 is true, statement-2 is true,statement-2 is not a correct explanation for statement-1

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Solution

The correct option is D Statement-1 is true, statement-2 is true,statement-2 is not a correct explanation for statement-1
Gravitational potential is always negative and adding gravitational potential from a number of sources would never give zero potential.
However sources can be aligned such that the gravitational field vectors cancel each other to give overall zero field.

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Similar questions

- 1 :

0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

a > 1

- 2 :

a > 1, {log}_{a} x

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

C_{r m s} = \sqrt{\frac{3 P V}{M}}

n \geq 2,

\frac{1}{\sqrt{1}} + \frac{1}{\sqrt{2}} + . . . + \frac{1}{\sqrt{n}} > \sqrt{n}

\sqrt{n (n + 1)} < n + 1

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