Assertion :For an ideal gas (∂H∂P)T=0 Reason: Enthalpy of an ideal gas is a function of temperature only.
Assume 1 mole of an ideal gas.
The ideal gas is defined as a gas which obeys the following equation of state:
PV = RT
The internal energy of an ideal gas is a function of temperature only. That is,
u = u(T)
Using the definition of enthalpy and the equation of state of an ideal gas to yield,
h = u + P v = u + RT
Since R is a constant and u = u(T), it follows that the enthalpy of an ideal gas is also a function of temperature only.
h = h(T)
So, (∂H/∂P)T=0 as derivative will be zero.
Hence, option A is correct