Solving a system of linear equation in two variables
Assertion :If...
Question
Assertion :If a,b,c are in Arithmetic Progression, then the system of equations: 3x+4y+5z=a ------- (1) 4x+5y+6z=b -------(2) 5x+6y+7z=c ------(3) are consistent. Reason: If |A|≠0, the system of equations AX=B is consistent.
A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Assertion is incorrect but Reason is correct
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Solution
The correct option is B Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion If |A|≠0, A is invertible and we can write AX=B as X=A−1B. ∴AX=B has a unique solution and hence is consistent. Subtracting (2) from (3) and (1) from (2), we get the system of equation as 3x+4y+5z=a -------(4) x+y+z=b−a -------(5) x+y+z=c−b -------(6) As a,b,c are in A.P. b−a=c−b ∴ the last two equations are identical. From (4) and (5) we obtain x=4b−5a+k y=4a−3b−2k z=k where k is an arbitrary complex number. Thus, the system of equations in statement-1 is consistent. Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion.