wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Assertion :If |z|<āˆš2āˆ’1 ,then |z2+2zcosB|<1. Reason: |z1+z2|<|z1|+|z2| & |cosB|<1.

A
Both (A) & (R) are individually true & (R) is correct explanation of (A).
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Both (A) & (R) are individually true but (R) is not the correct (proper) explanation of (A).
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
C
(A) is true (R) is false.
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
D
(A) is false (R) is true.
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
Open in App
Solution

The correct option is A Both (A) & (R) are individually true & (R) is correct explanation of (A).
|z2+2zcosB|<|z|2+|2zcosB|
(By reason)
=|z|2+2|z||cosB|<(21)2+2(21).1
=322+222=1
|z2+2zcosB|<1 (Assertion (A) is true)

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon