Assertion :If f(x)=xn then f(1)+f′(1)1+f′′(1)2!+f′′′(1)3!+...+nf(1)n!=2n Reason: If (1+x)n=n∑r=0nCrxr, then n∑r=0nCr=2n
A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Assertion is correct but Reason is incorrect
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Both Assertion and Reason are incorrect
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for Assertion f(x)=f(1)+f′(1)(x−1)+f′′(1)2!(x−1)2+....+fn(1)n!(x−1)n
f(x)=xn⟹ put x=2⟹f(1)+f′(1)1+f′′(1)2!+⋯+fn(1)n!=2n