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Question

Assertion :If f(x)=xn then f(1)+f(1)1+f′′(1)2!+f′′′(1)3!+...+nf(1)n!=2n Reason: If (1+x)n=nr=0nCrxr, then nr=0nCr=2n

A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Both Assertion and Reason are incorrect
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Solution

The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
f(x)=f(1)+f(1)(x1)+f′′(1)2!(x1)2+....+fn(1)n!(x1)n
f(x)=xn put x=2f(1)+f(1)1+f′′(1)2!++fn(1)n!=2n
(1+x)n=nr=0Crxr
Put x=1
nr=0Cr=(1+1)n=2n

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