Assertion :If log0.2(x+1x)≥1, then x∈[−1.25,−1). Reason: If 0<a<1, logax≥logay⇔y≥x>0.
A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion.
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion.
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C
Assertion is correct but Reason is incorrect.
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D
Assertion is incorrect but Reason is correct.
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Solution
The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for Assertion. log0.2(x+1x) is valid when x+1x>0 ⇒x∈(−∞,−1)∪(0,∞)....(1) log0.2(x+1x)≥1 ⇒x+1x≤15 ⇒4x+5x≤0 ⇒x∈[−54,0).....(2) From (1) & (2), we get x∈[−1.25,−1) Ans: A