Assertion- If - be the angle between A- and B- then tan-A-B-A-B- Reason- A - B is perpendicular to A - BA- If both assertion and reason are true and the reason is the correct explanation of the assertion-B- If both assertion and reason are true but reason is not the correct explanation of the assertion-C- If assertion is true but reason is false-D- If the assertion and reason both are false-E- If assertion is false but reason is true-

The correct option is D If the assertion and reason both are false.A×BA . B = AB sinθ n̂AB cosθ = tanθ n̂ and A . B is a scalar quantity. nbsp; ...

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Byju's Answer

Standard XII

Physics

Multiplication with Vectors

Assertion: If...

Question

Assertion: If $θ$ be the angle between $\to A$ and $\to B$ , then $tan θ = \frac{\to A \times \to B}{\to A . \to B}$
Reason: $\to A \times \to B$ is perpendicular to $\to A . \to B$

If both assertion and reason are true and the reason is the correct explanation of the assertion.

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If both assertion and reason are true but reason is not the correct explanation of the assertion.

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If assertion is true but reason is false.

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If the assertion and reason both are false.

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If assertion is false but reason is true.

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Solution

The correct option is D If the assertion and reason both are false.
$\frac{\to A \times \to B}{\to A . \to B} = \frac{A B sin θ^n}{A B cos θ} = tan θ^n and \to A . \to B$ is a scalar quantity.

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Assertion: If θ be the angle between →A and →B, then tanθ=→A×→B→A.→B Reason: →A×→B is perpendicular to →A.→B

The correct option is D If the assertion and reason both are false.→A×→B→A.→B=AB sinθ ^nAB cosθ=tanθ ^n and →A.→B is a scalar quantity.

Assertion: If $θ$ be the angle between $\to A$ and $\to B$ , then $tan θ = \frac{\to A \times \to B}{\to A . \to B}$
Reason: $\to A \times \to B$ is perpendicular to $\to A . \to B$

The correct option is D If the assertion and reason both are false.
$\frac{\to A \times \to B}{\to A . \to B} = \frac{A B sin θ^n}{A B cos θ} = tan θ^n and \to A . \to B$ is a scalar quantity.