Assertion :If xsin3θ+ycos3θ=sinθcosθ and xsinθ=ycosθ, then x2+y2=1. Reason: 4sin3θ=3sinθ−sin3θ and 4cos3θ=3cosθ+cos3θ
Reason:
sin3θ=3sinθ−4sin3θ⇒4sin3θ=3sinθ−sin3θcos3θ=4cos3θ−3cosθ⇒4cos3θ=3cosθ+cos3θ
Assertion:
xsin3θ+ycos3θ=sinθcosθ⇒xsinθ⋅sin2θ+ycosθ⋅cos2θ=sinθcosθ
xsinθ=ycosθ
We get
xsinθ⋅sin2θ+xsinθ⋅cos2θ=sinθcosθ⇒xsinθ=sinθcosθ⇒x=cosθ⇒y=sinθ⇒x2+y2=1
Hence assertion and reason both are true but
reason is not correct explanation of Assertion