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Question

Assertion :If xsin3θ+ycos3θ=sinθcosθ and xsinθ=ycosθ, then x2+y2=1. Reason: 4sin3θ=3sinθsin3θ and 4cos3θ=3cosθ+cos3θ

A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Assertion is incorrect but Reason is correct
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Solution

The correct option is B Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

Reason:
sin3θ=3sinθ4sin3θ4sin3θ=3sinθsin3θcos3θ=4cos3θ3cosθ4cos3θ=3cosθ+cos3θ
Assertion:
xsin3θ+ycos3θ=sinθcosθxsinθsin2θ+ycosθcos2θ=sinθcosθ
xsinθ=ycosθ
We get
xsinθsin2θ+xsinθcos2θ=sinθcosθxsinθ=sinθcosθx=cosθy=sinθx2+y2=1
Hence assertion and reason both are true but reason is not correct explanation of Assertion


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