Assertion :If z=i+2i2+3i3+.............+32i32, then z,¯¯¯z,z & ¯¯¯z forms the vertices of square on argand plane. Reason: z,¯¯¯z,z,¯¯¯z are situated at the same distance from the origin on argand plane.
A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Assertion is incorrect but Reason is correct
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Solution
The correct option is B Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion z=i+2i2+3i3+...32i32 And iz=i2+2i3+3i4+...31i32+32i33 Now z(1−i)=i+i2+i3+..i32−32i33 z(1−i)=i(i32−1)i−1−32i32.i z(1−i)=−32.i since i32=1 Or z=−32i1−i =−16.(i)(1+i) =−16(i−1) =16(1−i) =16√2[1−i√2] =16√2.e−iπ4 Hence z=16√2.e−iπ4 ¯z=16√2.eiπ4. Now both z and ¯z are equidistant from the origin, and origin, z,¯z forms a right angled isosceles triangle.