CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Assertion :If z=i+2i2+3i3+.............+32i32, then z,¯¯¯z,z & ¯¯¯z forms the vertices of square on argand plane. Reason: z,¯¯¯z,z,¯¯¯z are situated at the same distance from the origin on argand plane.

A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Assertion is correct but Reason is incorrect
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Assertion is incorrect but Reason is correct
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
z=i+2i2+3i3+...32i32
And
iz=i2+2i3+3i4+...31i32+32i33
Now
z(1i)=i+i2+i3+..i3232i33
z(1i)=i(i321)i132i32.i
z(1i)=32.i since i32=1
Or
z=32i1i
=16.(i)(1+i)
=16(i1)
=16(1i)
=162[1i2]
=162.eiπ4
Hence
z=162.eiπ4
¯z=162.eiπ4.
Now both z and ¯z are equidistant from the origin, and origin, z,¯z forms a right angled isosceles triangle.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction to Limits
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon