wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Assertion :In case of charged spherical shells, E-r graph is discontinuous while V-r graph is continuous. Reason: According to Gauss theorem the charge inside a closed surface can only produce electric field at some point.

A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Assertion is correct but Reason is incorrect
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Both Assertion and Reason are incorrect
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C Assertion is correct but Reason is incorrect
The Electric field inside the spherical shell is 0 by Gauss' law. But at surface, it is given as E=Q/4πϵoR2. So the Er graph is discontinuous.
While potential inside the spherical shell is V=kQ/r,r<R
At surface and outside, V=kQ/R
So the V-r graph is continuous.
So assertion is correct.
The reason is incorrect, as any charge can produce electric field at any point, not just charge inside a closed surface.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Torque on a Magnetic Dipole
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon