Assertion :In chemisorption, adsorption keeps on increasing with temperature. Reason: Heat keeps on providing more and more activation energy.

If both (A) and (R) are true and (R) is the correct explanation of (A).

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If both (A) and (R) are true, but (R) is not the correct explanation of (A).

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If (A) is correct, but (R) is incorrect.

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If (A) and (R) are both incorrect.

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Solution

The correct option is D If (A) and (R) are both incorrect.
Chemisorption requires high activation energy and referred to as activated adsorption. As temperature increases adsorption first increases and then decreases . Also, activation energy for a reaction is constant and doesn't change with temperature. So , both assertion and reason given are wrong and answer is option D.

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Similar questions

Q. Assertion :In chemisorption, adsorption first increases with temperature and then decreases. Reason: Heat keeps on providing more and more activation energy.

Assertion (A) The enthalpy of reaction remains constant in the presence of a catalyst.

Reason (R) A catalyst participating in the reaction forms different activated complex and lowers down the activation energy but the difference in enrgy of reactant and product remains the same.

(a) Both assertion and reason are correct and the reason is correct explanation of assertion
(b) Both assertion and reason are correct, but reason does not explain assertion.
(c) Assertion is correct, but reason is incorrect
(d) Both assertion and reason are incorrect
(e) Assertion is incorrect but reason is correct.

Q. Assertion: Average kinetic energy in one oscillation during

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\frac{1}{4} m ω^{2} A^{2}

.
Reason: Maximum kinetic energy is

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Q. Given below are assertion and reason. Point out if both are true with the reason being a correct explanation (A), both true but the reason is not correct explanation (B), the assertion is true but the reason is wrong (C) and both are wrong (D).

Assertion.

C_{4}

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In the following questions, a statement of assertion is followed by a statement of reason. Mark the correct choice as:
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