Assertion :In cyclic process, initial and final state are same. Therefore, net work done is zero. Reason: Initial and final temperature is equal, therefore change in initial energy is zero.

Statement-1 is false, Statement-2 is true.

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Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1

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Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1

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Statement-1 is true, Statement-2 is false

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Solution

The correct option is A Statement-1 is false, Statement-2 is true.
A cyclic process begins and ends at the same state.
Hence, the change in all state functions like internal energy and enthalpy will be zero.

However, heat supplied and work done are path functions and they depend on the path taken between the states and hence they need not be zero.

So, the assertion is false and the reason is true.

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Similar questions

- 1 :

0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

a > 1

- 2 :

a > 1, {log}_{a} x

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

n \geq 2,

\frac{1}{\sqrt{1}} + \frac{1}{\sqrt{2}} + . . . + \frac{1}{\sqrt{n}} > \sqrt{n}

\sqrt{n (n + 1)} < n + 1

Statement - I: $C l^{-} a n d C a^{2 +}$ are isoelectronic species.
Statement - II: Isoelectronic species should have same charges.

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