Assertion : In ΔABC, median AD is produced to X such that AD = DX. Then, ABXC is a parallelogram.
Reason : Diagonals AX and BC bisect each other at right angles.
Which of the following is correct?
If assertion is true but reason is false
In quadrilateral ABXC, we have,
AD = DX [Given]
BD = DC [AD is given as median]
∠ADB = ∠XDC [Vertically Opposite Angles]
Thus, ΔADB is congruent to ΔXCD by SAS congruency.
Hence, AB = XC [CPCT] (1)
∠BAD = ∠CXD [CPCT]
∠BAD and ∠CXD form a pair of alternate interior angles and since they are equal, AB||XC (2)
From (1) and (2), ABXC is proved to be a parallelogram, as we have proved that one pair of opposite sides are parallel and equal.
So, diagonals AX and BC bisect each other.
∴ ABXC is a parallelogram
∴ Assertion is true but reason is false.