Parallelograms on the Same Base and between the Same Parallels Are Equal in Area
Assertion : I...
Question
Assertion : In ΔABC, median AD is produced to X such that AD = DX. Then, ABXC is a parallelogram. Reason : Diagonals AX and BC bisect each other at right angles. Which of the following is correct?
A
If both assertion and reason are true and reason is the correct explanation of assertion
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B
If both assertion and reason are true but reason is not the correct explanation of assertion
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C
If assertion is true but reason is false
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D
If assertion is false but reason is true
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Solution
The correct option is CIf assertion is true but reason is false In quadrilateral ABXC, we have, AD = DX[Given] BD = DC[AD is given as median] ∠ADB = ∠XDC[Vertically Opposite Angles] Thus, ΔADB is congruent to ΔXCD by SAS congruency.
Hence, AB = XC[CPCT] (1) ∠BAD = ∠CXD[CPCT] ∠BAD and ∠CXD form a pair of alternate interior angles and since they are equal, AB||XC (2) From (1) and (2), ABXC is proved to be a parallelogram, as we have proved that one pair of opposite sides are parallel and equal. So, diagonals AX and BC bisect each other. ∴ ABXC is a parallelogram ∴Assertion is true but reason is false.