Assertion :In the following reaction:
$S O_{2} + 2 H_{2} S ⟶ 3 S + 2 H_{2} O$
$1$ mole $S O_{2}$ and $1$ mole $H_{2} S$ form $3$ moles sulphur. Reason: $1$ mole $S O_{2}$ and $2$ moles $H_{2} S$ form $3$ moles sulphur and $2$ moles $H_{2} O$ .

Both Assertion and Reason are are true and Reason is the correct explanation for Assertion

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Both Assertion and Reason are true but Reason is not the correct explanation for Assertion

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Assertion is true but Reason is false

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Assertion is false but Reason is true

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Solution

The correct option is D Assertion is false but Reason is true
$S O_{2} + 2 H_{2} S ⟶ 3 S + 2 H_{2} O$
1 mole 2 mole 3 mole 2 mole
So, according to balanced reaction, $1$ mole of $S O_{2}$ reacts with $2$ moles of $H_{2} S$ and $3$ moles of $S$ and $2$ moles of $H_{2} O$ forms.

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H_{2}

O_{2}

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P (A) = \frac{1}{3}

P (B) = \frac{2}{3}

P (A \cup B) \geq \frac{2}{3}

P (B) > P (A)

P (A \cup B) \geq P (B)

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