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Question

Assertion :(cosA+cosBsinA−sinB)n+(sinA+sinBcosA−cosB)n
=2cotn(A−B2) if n is even
=0 if n is odd. Reason: cosA+cosBsinA−sinB=cotA−B2.

A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Assertion is incorrect but Reason is correct
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Solution

The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

cosA+cosBsinAsinB=2cos(A+B2)cos(AB2)2cos(A+B2)sin(AB2)=cot(AB2)

sinA+sinBcosAcosB=2sin(A+B2)cos(AB2)2sin(A+B2)sin(AB2)=cot(AB2)

(cosA+cosBsinAsinB)n+(sinA+sinBcosAcosB)n=(cot(AB2))n+(cot(AB2))n

If n is even
(cosA+cosBsinAsinB)n+(sinA+sinBcosAcosB)n=2cot(AB2)
Hence, option 'A' is correct.


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