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Question

Assertion :Let A(θ)=[cosθ+sinθ2sinθ2sinθcosθsinθ]

A(π/3)3=I
Reason: A(θ)A(ϕ)=A(θ+ϕ)

A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Assertion is incorrect but Reason is correct
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Solution

The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
Given that A(θ)=[cosθ+sinθ2sinθ2sinθcosθsinθ]

Let A(θ)A(ϕ)=[abbc]
where a=(cosθ+sinθ)(cosϕ+sinϕ)2sinθsinϕ
=(cosθcosϕsinθsinϕ)+(sinθcosϕ+cosθsinϕ)
=cos(θ+ϕ)+sin(θ+ϕ);
b=2[sinϕ(cosθ+sinθ)+sinθ(sinϕ+cosϕ)]
and c=2sinθsinϕ+(cosθsinθ)(cosϕsinϕ)
=cosθcosϕsinθsinϕ(sinθcosϕ+cosϕsinθ)
=cos(θ+ϕ)sin(θ+ϕ)
Thus, A(θ)A(ϕ)=A(θ+ϕ)
A(θ)2=A(2θ)
A(θ)3=A(2θ)A(θ)=A(3θ)
A(π/3)3=A(π)=I
Thus both the Assertion and Reason are correct and Reason is the correct explanation for Assertion.

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