Assertion :Let A=x∣x is a prime number<25 , then the number of distinct rationals except one whose numerator & denominator are elements of A is 36 . Reason: pq is a rational ∀q≠0, HCF of (p,q)is equal to 1.
A
Both (A) & (R) are individually true & (R) is correct explanation of (A),
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Both (A) & (R) are individually true but (R) is not the correct (proper) explanation of (A).
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(A)is true but (R) is false,
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(A)is false but (R) is true.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D (A)is false but (R) is true. As A is a prime <25∴A={2,3,5,7,11,13,17,19,23}∴n(A)=9 We needed two distinct numbers out of 9 ∴ Required number of ways =2×9C2=72 ∴ Assertion (A) is false and Reason (R) is correct