Assertion :Let f is odd function, then value of ∫a−af(sinx)f(cosx)+f(sin2x)dx is zero Reason: For odd function ∫a−af(x)dx=0
A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Both Assertion and Reason are incorrect
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Solution
The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for Assertion Since the denominator is even & the numerator f(sin(−x))=f(−sinx)=−f(sinx) as f is odd. ∴f(sinx)f(cosx)+f(sin2x) is an odd function ∴∫a−af(sinx)f(cosx)+f(sin2x)dx=0