Assertion :Locus of z satisfying the equation |z−1|+|z−8|=5 is an ellipse Reason: Sum of focal distances of any point on ellipse is constant.
A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Assertion is incorrect and Reason is correct
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Solution
The correct option is D Assertion is incorrect and Reason is correct Let z=x+iy Therefore |z−1|+|z−8|=5 √y2+(x−1)2+√y2+(x−8)2=5 √y2+(x−1)2=5−√y2+(x−8)2 y2+(x−1)2=25+y2+(x−8)2−10√y2+(x−8)2 10√y2+(x−8)2=25+(x−8)2−(x−1)2 10√y2+(x−8)2=25−7(2x−9) 10√(y2+(x−8)2=25−14x+63 10√y2+(x−8)2=88−14x 5√y2+(x−8)2=44−7x 25(y2+(x−8)2)=176+49x2−616x 25y2+25x2−400x+1600=176−616x+49x2 24x2−25y2−216x=1424 This represents the equation of an hyperbola.