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Question

Assertion :Locus of z satisfying the equation |z1|+|z8|=5 is an ellipse Reason: Sum of focal distances of any point on ellipse is constant.

A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Assertion is incorrect and Reason is correct
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Solution

The correct option is D Assertion is incorrect and Reason is correct
Let z=x+iy
Therefore
|z1|+|z8|=5
y2+(x1)2+y2+(x8)2=5
y2+(x1)2=5y2+(x8)2
y2+(x1)2=25+y2+(x8)210y2+(x8)2
10y2+(x8)2=25+(x8)2(x1)2
10y2+(x8)2=257(2x9)
10(y2+(x8)2=2514x+63
10y2+(x8)2=8814x
5y2+(x8)2=447x
25(y2+(x8)2)=176+49x2616x
25y2+25x2400x+1600=176616x+49x2
24x225y2216x=1424
This represents the equation of an hyperbola.

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