Question

Assertion :Maximum possible height attained by a projectile is $\frac{u^2}{2g}$, where u is initial velocity Reason: To attain maximum height, a particle is thrown vertically upwards at $\theta ={90}^o$ to the ground.
$H=\frac{u^2}{2g}si{n}^2\theta \Rightarrow H_{max}=\frac{u^2}{2g}$

• A. Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
• B. Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
• C. Assertion is correct but Reason is incorrect
• D. Both Assertion and Reason are incorrect

Answer 1

The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

For a projectile motion, when a body is thrown in a angle $\theta$ with the horizontal with velocity $u$, the body attains maximum height $H=\frac{u^2{\sin }^2\theta }{2g}$

When the body is thrown vertically, $\theta ={90}^o$

So, maximum height $H=\frac{u^2\sin {90}^o}{2g}=\frac{u^2}{2g}$