Assertion: Orbiting satellite or body has K.E. of always less than that of Potential energy.
Reason : For any bound state, the magnitude of potential energy is always twice that of kinetic energy (K.E.)

Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1

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Statement-1 is True, Statement-2 is True; Statement-2 is not a correct explanation for Statement-1

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Statement-1 is True, Statement-2 is False

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Statement-1 is False, Statement-2 is True

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Solution

The correct option is A Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1
For any bound state the magnitude of potential energy is double than the kinetic energy and with a negative sign.
It is because of this negative total energy that the satellite stays in the state.

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Similar questions

- 1 :

0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

a > 1

- 2 :

a > 1, {log}_{a} x

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

I

\to L = I \to ω

II

\to τ = \frac{d \to L}{d t}

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