Assertion : $P b S i F_{6}$ + $H_{2} S i F_{6}$ + gelatine is taken as electrolyte in electrolytic refining of lead. Reason: Discharge potential of $P b^{2 +}$ is less than $H^{+}$ .

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

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Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

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Assertion is correct but Reason is incorrect

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Assertion is in correct and Reason is correct

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Solution

The correct option is B Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
Anode is impure lead and cathode is pure lead.
The electrolyte is a mixture of $P b S i F_{6}, H_{2} S i F_{6}$ and $g e l a t i n$ .
Pure metal from anode dissolves and is deposited on the cathode.
Discharge potential of $P b^{2 +}$ is less than $H^{+}$ .
Hence, hydrogen is not liberated at cathode.
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion.

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Assertion :PbSiF6 + H2SiF6 + gelatine is taken as electrolyte in electrolytic refining of lead. Reason: Discharge potential of Pb2+ is less than H+.

Assertion : $P b S i F_{6}$ + $H_{2} S i F_{6}$ + gelatine is taken as electrolyte in electrolytic refining of lead. Reason: Discharge potential of $P b^{2 +}$ is less than $H^{+}$ .