Question

Assertion: Points A(6, 4), B(-4, -6) and C(4, 6) are such that AB =$\sqrt{200}$, BC= $\sqrt{208}$, AC= $\sqrt{8}$, Since AB+BC>AC, points A, B and C from a triangle.

Reason: If $B{C}^2=A{B}^2+A{C}^2$, then $\Delta ABC$ is a right triangle, right angled at A.

• A. If both assertion and reason are true and reason is te correct explanation of assertion
• B. If both assertion and reason are true but reason is not the correct explanation of assertion.
• C. If assertion is true but reason is false.
• D. If assertion is false but reason is true.

Answer 1

The correct option is B If both assertion and reason are true but reason is not the correct explanation of assertion.



Sum of the two sides is greater than third side
$\therefore AB+BC>ACandAB+AC>BC$
$\because$ ABC is a triangle
Also $B{C}^2=A{B}^2+A{C}^2$
$(\sqrt{208}{)}^2=(\sqrt{200}{)}^2+{\sqrt{8}}^{2}208=200+8208=208$
$\therefore$ ABC is right angled triangle
Assertion: True; Reason: True but is not the correct explanation of assertion