Assertion :Power of a glass convex lens in air is $+ 6 D$ , then power of the same convex lens in water will be $+ 2 D$ Reason: $P = (\frac{μ_{l}}{μ_{m}} - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}})$

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

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Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

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Assertion is correct but Reason is incorrect

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Both Assertion and Reason are incorrect

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Solution

The correct option is D Both Assertion and Reason are incorrect
Power of the lens is reciprocal of focal length. On immersion in water focal length of the lens increases about $4$ times, thus power of the lens will decrease 4 times.
Power of a glass convex lens in air is $+ 6 D$ , then power of the same convex lens in water will be $\frac{1}{4} \times 6 D = + \frac{3}{2} D$

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Assertion :Power of a glass convex lens in air is +6D, then power of the same convex lens in water will be +2D Reason: P=(μlμm−1)(1R1−1R2)

Assertion :Power of a glass convex lens in air is $+ 6 D$ , then power of the same convex lens in water will be $+ 2 D$ Reason: $P = (\frac{μ_{l}}{μ_{m}} - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}})$