Assertion : ${S b}_{2} S_{3}$ is not soluble in yellow ammonium sulphide. Reason: The common ion effect due to $S^{2 -}$ ions reduce solubility of ${S b}_{2} S_{3}$ .

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

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Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

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Assertion is correct but Reason is incorrect

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Both Assertion and Reason are incorrect

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Solution

The correct option is D Both Assertion and Reason are incorrect
$S b_{2} S_{3}$ react with yellow ammonia sulphate and hence it is soluble in yellow ammonia sulphide and produces thiosalts.
The following reaction takes place:
$S b_{2} S_{3}$ + $3 (N H_{4})_{2}$ $S$ $⟶$ $2$ $(N H_{4})_{3}$ $S b S_{2}$
Hence assertion is incorrect.
Ordinary ammonium sulphates cannot dissolve $S b_{2} S_{3}$ but yellow ammonium sulphates. It is because yellow ammonium sulphates contains excess of sulphur. So the common ion effect due to S $^{2 -}$ ion will increase solubility of $S b_{2} S_{3}$
Hence reason is incorrect.

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Assertion :Sb2S3 is not soluble in yellow ammonium sulphide. Reason: The common ion effect due to S2− ions reduce solubility of Sb2S3.

Assertion : ${S b}_{2} S_{3}$ is not soluble in yellow ammonium sulphide. Reason: The common ion effect due to $S^{2 -}$ ions reduce solubility of ${S b}_{2} S_{3}$ .