Assertion :Standard enthalpy of isomerisation of enantiomer into the other is zero. Reason: The two enantiomers of any chiral compound have the same enthalpy of formation.

Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1.

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Statement-1 is true, statement-2 is true and statement-2 is is NOT the correct explanation for statement-1.

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Statement-1 is true, statement-2 is false.

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Statement-1 is true, statement-2 is true.

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Solution

The correct option is A Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1.
An enantiomer is one of two stereoisomers that are mirror images of each other that are non-superposable (not identical).
So enantiomers are not different in bonding of atoms, they are just different in their stereo specific positions.
So two enantiomers of any chiral compound have the same enthalpy of formation.
And because of that standard enthalpy of isomerisation of enantiomer into the other is zero.( $△ H = H_2 - H_1 a n d H_2 = H_1 s o △ H = 0$ )

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