Assertion :STATEMENT-1 : 2,2-dimethylpropanal undergoes cannizzaro reaction with concentrated $N a O H$ . Reason: STATEMENT-2 : Cannizzaro reaction is a disproportionation reaction.

STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is a correct explanation for STATEMENT-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

STATEMENT-1 is True, STATEMENT-2 is False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

STATEMENT-1 is False, STATEMENT-2 is True

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1
Even though $(C H_{3})_{2} C H - C H O$ has $α$ -hydrogen, it undergoes Cannizzaro reaction, due to + I effects of methyl group and easy transfer of $H^{-}$ ion from one molecule to another.

Suggest Corrections

Similar questions

- 1 :

0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

a > 1

- 2 :

a > 1, {log}_{a} x

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

n \geq 2,

\frac{1}{\sqrt{1}} + \frac{1}{\sqrt{2}} + . . . + \frac{1}{\sqrt{n}} > \sqrt{n}

\sqrt{n (n + 1)} < n + 1

\sim (p \leftrightarrow\sim q)

p \leftrightarrow q

\sim (p \leftrightarrow\sim q)

Join BYJU'S Learning Program