CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Assertion :Statement 1:(666......ndigits)2+(888......ndigits)=(444....2ndigits) and Reason: Statement 2 :111....112times is a prime number

A
STATEMENT -1 is true , STATEMENT -2 is true;STATEMENT 2 is NOT a correct explanation for STATEMENT -1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
STATEMENT -1 is true , STATEMENT -2 is true;STATEMENT 2 is a correct explanation for STATEMENT -1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
STATEMENT -1 is true , STATEMENT -2 is False
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
STATEMENT -1 is false , STATEMENT -2 is true
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C STATEMENT -1 is true , STATEMENT -2 is False
Statement 1 is true and statement 2 is false
Statement 1:
(66)2+(88)=44444356+88=44444444=4444(666)2+(888)=444444443556+888=444444444444=444444

Statement 2:
If we take 1 and 11, the statement is satisfied, but for 111 which is divisible by 3 and 37, it is a composite number.
Thus, if (111....n) when n is a multiple of 3. The number is composite
Hence statement is false.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Types of Sets
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon