Question

Assertion :Statement 1 (Assertion)- The bond order of $NO$ is $2.5$ while the bond order of $N{O}^{+}$ is $3$. Reason: Statement 2 (Reason)- The electron removed to convert $NO$ into $N{O}^{+}$ is from an anti-bonding orbital.

• A. Statement 1 is True, statement 2 is True; statement 2 is a correct explanation for statement 1.
• B. Statement 1 is True, statement 2 is True; statement 2 is not a correct explanation for statement 1.
• C. Statement 1 is True, statement 2 is False.
• D. Statement 1 is False, statement 2 is True.

Answer 1

The correct option is A Statement 1 is True, statement 2 is True; statement 2 is a correct explanation for statement 1.

During the ionisation $NO\to N{O}^{+}$, the bond order
increases from 2.5 to 3 and the magnetic character changes from
paramagnetic to diamagnetic.

For $NO$,

$1s^2\ast 1s^{2}2s^2\ast 2s^{2}2p{z}^{2}2p{x}^{2}2p{y}^2\ast 2p{x}^1\ast 2p{y}^0$

Bond Order = $\frac{6-1}{2}$ = 2.5

For $N{O}^{+}$,

$1s^2\ast 1s^{2}2s^2\ast 2s^{2}2p{z}^{2}2p{x}^{2}2p{y}^2$

Bond Order = $\frac{10-4}{2}$ = 3