Assertion :Statement - 1 : $P O F_{3}$ exist but $N O F_{3}$ does not exist. Reason: Statement - 2 : 'P' can form five bonds by expanding its octet while 'N' can not expand its octet to form five bonds.

Statement - 1 is true, statement - 2 is true and statement - 2 is correct explanation for statement - 1.

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Statement - 1 is true, statement - 2 is true and statement - 2 is NOT the correct explanation for statement - 1.

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Statement - 1 is true, statement - 2 is false.

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Statement - 1 is false, statement - 2 is true.

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Solution

The correct option is D Statement - 1 is false, statement - 2 is true.
$N O F_{3}$ exist due to dative bond between N and O.
Also, 'P' can form five bonds by expanding its octet while 'N' can not expand its octet to form five bonds. is a true statement.

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n \geq 2,

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\frac{1}{\sqrt{1}} + \frac{1}{\sqrt{2}} + . . . + \frac{1}{\sqrt{n}} > \sqrt{n}

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Q. Statement - 1:

\sim (p \leftrightarrow\sim q)

is equivalent to

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.
Statement - 2:

\sim (p \leftrightarrow\sim q)

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Statement 2: $\sim (p \leftrightarrow\sim q)$ is tautology.
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Assertion :Statement - 1 : POF3 exist but NOF3 does not exist. Reason: Statement - 2 : 'P' can form five bonds by expanding its octet while 'N' can not expand its octet to form five bonds.

The correct option is D Statement - 1 is false, statement - 2 is true.NOF3 exist due to dative bond between N and O.Also, 'P' can form five bonds by expanding its octet while 'N' can not expand its octet to form five bonds. is a true statement.

Assertion :Statement - 1 : $P O F_{3}$ exist but $N O F_{3}$ does not exist. Reason: Statement - 2 : 'P' can form five bonds by expanding its octet while 'N' can not expand its octet to form five bonds.

The correct option is D Statement - 1 is false, statement - 2 is true.
$N O F_{3}$ exist due to dative bond between N and O.
Also, 'P' can form five bonds by expanding its octet while 'N' can not expand its octet to form five bonds. is a true statement.