Question

Assertion :statement-1 : $FeC{l}_3$ is stable but $Fe{I}_3$ is unstable. Reason: Statement-2 : $I^{-}$ is a strong reductant and $F{e}^{3+}$ is oxidant and thus, $I^{-}$ reduces $F{e}^{3+}$ to $F{e}^{2+}$. On the other hand, $C{l}^{-}$ is weak reductant.

• A. Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1.
• B. Statement-1 is true, statement-2 is true and statement-2 is not the correct explanation for statement-1.
• C. Statement-1 is true, statement-2 is false.
• D. Statement-1 is false, statement-2 is true.

Answer 1

The correct option is A Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1.

Iodide ion being a strong reductant, reduces Fe(III) ion (which is a strong oxidant) to Fe(II) .

Hence, $Fe{I}_3$ is unstable and is converted to $Fe{I}_2$.

On the other hand, $FeC{l}_3$ is stable as chloride ion is a weak reductant.

Thus, statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1.