Assertion :Statement-1 : In water, orthoboric acid behaves as a weak monobasic Lewis acid. Reason: Statement-2 : In water, orthoboric acid acts as a proton donor.

Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.

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Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1

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Statement-1 is True, Statement-2 is False

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Statement-1 is False, Statement-2 is True

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Solution

The correct option is C Statement-1 is True, Statement-2 is False
Orthoboric acid acts as Lewis-acid in water not as proton donar because it completes its octet by accepting $O H^{-}$ from water.

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Read the following and select one the correct answer.

Statement I: In water, orthoboric acid behaves as a weak monobasic acid

Statement II: In water, orthoboric acid acts as a proton donor

- 1 :

0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

a > 1

- 2 :

a > 1, {log}_{a} x

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

n \geq 2,

\frac{1}{\sqrt{1}} + \frac{1}{\sqrt{2}} + . . . + \frac{1}{\sqrt{n}} > \sqrt{n}

\sqrt{n (n + 1)} < n + 1

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