Assertion :Statement - 1 : $P b C l_{2} a n d A g C l$ precipitates can be separated by ammonia solution. Reason: Statement --2 : $P b C l_{2}$ precipitate is soluble in hot water and concentrated potassium chloride solution.

Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Statement-1 is True, Statement-2 is False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Statement-1 is False, Statement-2 is True

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1
Statement-1 : $A g C l + 2 N H_{3} ⟶ [A g (N H_{3})_{2}] C l (s o l u b l e c o m p l e x)$
$P b^{2 +} + 2 N H_{3} + 2 H_{2} O ⟶ P b (O H)_{2} ↓ (w h i t e) + 2 N {H_{4}}^{+}$
Statement - 2 : $P b C l_{2} ↓ + 2 C l^{-} ⟶ [P b C l_{4}]^{2 -} [s o l u b l e c o m p l e x]$

Suggest Corrections

Similar questions

- 1 :

0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

a > 1

- 2 :

a > 1, {log}_{a} x

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

n \geq 2,

\frac{1}{\sqrt{1}} + \frac{1}{\sqrt{2}} + . . . + \frac{1}{\sqrt{n}} > \sqrt{n}

\sqrt{n (n + 1)} < n + 1

\sim (p \leftrightarrow\sim q)

p \leftrightarrow q

\sim (p \leftrightarrow\sim q)

Join BYJU'S Learning Program