CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Assertion :Statement-1 : The enthalpy of neutralization of the reaction between HCl and NaOH is -13.7 kCal/mol. If the enthalpy of neutralization of oxalic acid (H2C2O4) by a strong base is -25.4 kCal/mol, then the enthalpy change (ΔH) of the process H2C2O42H++C2O24 is 11.7 kCal/mol. Reason: Statement -2 : H2C2O4 is a weak acid.

A
Statement- 1 is true, statement -2 is true and statement-2 is correct explanation for statement -1.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Statement- 1 is true, statement -2 is true and statement-2 is NOT the correct explanation for statement -1.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Statement- 1 is true, statement -2 is false.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Statement- 1 is false, statement -2 is true.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D Statement- 1 is false, statement -2 is true.
The enthalpy of neutralization of the reaction between HCl and NaOH is -13.7 kCal/mol. If the enthalpy of neutralization of oxalic acid (H2C2O4) by a strong base is -25.4 kCal/mol, then the enthalpy change (ΔH) of the process H2C2O42H++C2O24 is 213.725.4=2kCal/mol.
Also as its neutralisation energy is less than 13.7 so its a weak acid.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Enthalpy
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon