Assertion :Statement 1: The number of solution of n|sinx|=m|cosx| (wherem,n,ϵZ) in [0,2π] is independent of m and n Reason: Statement 2: Multiplying trigonometric function by a constant changes only the range of the function but period remains the same.
n|sin(x)|=m|cos(x)|
nm=|cot(x)|
Or
mn=|tan(x)|
Or
tan(x)=mn
Hence
x=tan−1(mn) and x=π+tan−1(mn).
And
tan(x)=−mn
Hence
x=−tan−1(mn) and x=π−tan−1(mn).
Now if n,m≠0 we therefore get 4 solutions
in the interval of [0,2π] independent of the values of m and n.