Assertion :STATEMENT-1 : Work done by a force on a body whose center of mass does not move may be non-zero. Reason: STATEMENT-2: Work done by a force depends on the displacement of the centre of mass.

Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Statement-1 is True, Statement-2 is False

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Statement-1 is False, Statement-2 is True.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C Statement-1 is True, Statement-2 is False
Work done depends on displacement of point of application of force and not on displacement of center of mass. Hence statement-2 is false.
As an example, if a ring is rotated about its center of mass by applying a tangential force, work is done but the center of mass of the ring does not move.

Suggest Corrections

Similar questions

- 1 :

0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

a > 1

- 2 :

a > 1, {log}_{a} x

Statement 1: Force acting on a body increases its kinetic energy from 200 J to 400 J and the force does a positive work on the body.

Statement 2: A force does a positive work on an object when the displacement due to the force is in the direction of the force itself.

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

2 m g

Join BYJU'S Learning Program