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CFSE in Octahedral and Tetrahedral Complexes

Assertion :St...

Question

Assertion :Statement $-$ 1 : $K_{3} [F e {(C N)}_{6}]$ is a low spin complex. Reason: Statement $-$ 2 : $F e^{2 +}$ ion in this complex undergoes $s p^{3} d^{2}$ hybridization.

Statement

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1 is true, Statement

-

2 is true and Statement

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2 is correct explanation for Statement

-

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Statement

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1 is true, Statement

-

2 is true and Statement

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2 is NOT the correct explanation for Statement

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Statement

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1 is true, Statement

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2 is false.

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Statement

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1 is false, Statement

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2 is true.

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Solution

The correct option is C Statement $-$ 1 is true, Statement $-$ 2 is false.
$K_{3} [F e (C N)_{6}]$
$F e^{+ 3}, d^{5}, d^{2} s p^{3}$ hybridisation, one unpaired electron; paramagnetic.
So its a low spin complex.

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Similar questions

Statement - 1: Complexes containing three bidentate ligands do not show optical activity.
Statement - 2: Octahedral complex $[C o (N H_{3})_{4} C l_{2}] C l$ shows geometrical isomerism.

Q. For every natural number

n \geq 2,

Statement 1:

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Statement 2:

\sqrt{n (n + 1)} < n + 1

Q. Statement

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0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

, where

a > 1

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Statement

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When

a > 1, {log}_{a} x

is an increasing function.

Q. Statement

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x^{{log}_{x} (3 - x)^{2}} = 25

, then

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Statement

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a^{{log}_{a} x} = x

, if

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and

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Q. Statement - 1:

\sim (p \leftrightarrow\sim q)

is equivalent to

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Statement - 2:

\sim (p \leftrightarrow\sim q)

is a tautology.

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Assertion :Statement − 1 : K3[Fe(CN)6] is a low spin complex. Reason: Statement − 2 : Fe2+ ion in this complex undergoes sp3d2 hybridization.

The correct option is C Statement − 1 is true, Statement − 2 is false.K3[Fe(CN)6]Fe+3,d5,d2sp3 hybridisation, one unpaired electron; paramagnetic.So its a low spin complex.

Assertion :Statement $-$ 1 : $K_{3} [F e {(C N)}_{6}]$ is a low spin complex. Reason: Statement $-$ 2 : $F e^{2 +}$ ion in this complex undergoes $s p^{3} d^{2}$ hybridization.

The correct option is C Statement $-$ 1 is true, Statement $-$ 2 is false.
$K_{3} [F e (C N)_{6}]$
$F e^{+ 3}, d^{5}, d^{2} s p^{3}$ hybridisation, one unpaired electron; paramagnetic.
So its a low spin complex.