Question

Assertion :Statement $-$ 1 : ${\left[Ti{\left(H_{2}O\right)}_6\right]}^{3+}$ is coloured while ${\left[Sc{\left(H_{2}O\right)}_6\right]}^{3+}$ is colourless. Reason: Statement $-$ 2 : d $-$ d transition is not possible in ${\left[Sc\left(H_{2}O\right)\right]}^{3+}$ because no d $-$ electron is present while possible for $T{i}^{3+}$ having d' system.

• A. Statement $-$ 1 is true, Statement $-$ 2 is true and Statement $-$ 2 is correct explanation for Statement $-$ 1.
• B. Statement $-$ 1 is true, Statement $-$ 2 is true and Statement $-$ 2 is NOT the correct explanation for Statement $-$ 1.
• C. Statement $-$ 1 is true, Statement $-$ 2 is false.
• D. Statement $-$ 1 is false, Statement $-$ 2 is true.

Answer 1

The correct option is A Statement $-$ 1 is true, Statement $-$ 2 is true and Statement $-$ 2 is correct explanation for Statement $-$ 1.

$\left[Ti\right(H_{2}O{)}_6{]}^{3+}$
$T{i}^{3+},d^1$ configuration have one unpaired electron so it is colourful.
$\left[Sc\right(H_{2}O{)}_6{]}^{3+}$
$S{c}^{+3},d^0$ configuration so don't have any d-electron for transition so it is colourless.