Assertion :Statement-I : If an aqueous solution of NaCl is electrolysed, the product obtained at the cathode is $H_{2}$ gas and not Na. Reason: Statement-II : Gases are liberated faster than the metals.

Statement-I is true, Statement-II is true; Statement-II is correct explanation for Statement-I.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Statement-I is true, Statement-II is true; Statement-II is NOT a correct explanation for statement-I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Statement-I is true, Statement-II is false

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Statement-I is false, Statement-II is true

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C Statement-I is true, Statement-II is false
As reduction potential of hydrogen ion is higher than sodium ion so hydrogen gas is obtained at cathode.

Suggest Corrections

Similar questions

Statement - I: $C l^{-} a n d C a^{2 +}$ are isoelectronic species.
Statement - II: Isoelectronic species should have same charges.

(p \land \sim q) \land (\sim p \land q)

(p \to q) \leftrightarrow (\sim q \to\sim p)

(p \land \sim q) \land (\sim p \land q)

(p \to q) \leftrightarrow (\sim q \to\sim p)

Statement - I: $C d$ is a transition element.
Statement - II: $C d$ and $C d^{2 +}$ both have completely filled $d -$ orbitals in their ground state.

Join BYJU'S Learning Program