Assertion :The 2 $^{n d}$ analytical group of cations consists of ions that form acid-insoluble sulfides. Reason: Any acid having anion belonging to 16 $^{t h}$ group of periodic group can be used to test 2 $^{n d}$ group because all of them have lower solubility products.

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

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Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

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Assertion is correct but Reason is incorrect

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Both Assertion and Reason are incorrect

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Solution

The correct option is C Assertion is correct but Reason is incorrect
The second anlytical group of cations consist of ions that form $a c i d - i n s o l u b l e$ $s u l f i d e s$ .
The reagent used can be any substance that gives $S^{2 -}$ ions in such solutions, mostly $H_{2} S,$ thioacetamide is used. The test with the $s u l f i d e$ ion must be conducted in the presence of dilute $H C l,$ so that the $s u l f i d e$ ion concentration is at minimum & precipitation of second group cations alone access.

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Assertion :The 2nd analytical group of cations consists of ions that form acid-insoluble sulfides. Reason: Any acid having anion belonging to 16th group of periodic group can be used to test 2nd group because all of them have lower solubility products.

Assertion :The 2 $^{n d}$ analytical group of cations consists of ions that form acid-insoluble sulfides. Reason: Any acid having anion belonging to 16 $^{t h}$ group of periodic group can be used to test 2 $^{n d}$ group because all of them have lower solubility products.