Assertion: The boiling point order of group $15$ hydrides is $P H_{3} < A s H_{3} < N H_{3} < S b H_{3} < B i H_{3}$ .
Reason: $H$ -bonding in $N H_{3}$ dominates van der Waals forces in bigger $S b$ molecules.

Both Assertion and reason are correct and Reason is the correct explanation for the Assertion

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Both Assertion and reason are correct and Reason is NOT the correct explanation for the Assertion

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Assertion is correct and reason is incorrect

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Assertion is incorrect and reason is correct

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Solution

The correct option is C Assertion is correct and reason is incorrect
Down the group, the boiling point of hydrides generally increases due to increase in van der Waals forces. But due to the presence of $H$ -bonding in $N H_{3}$ its boiling point is higher than that of $P H_{3}$ as well as $A s H_{3}$ but van der Waals forces in bigger Sb molecules dominates the $H$ -bonding in $N H_{3}$ and therefore the boiling point of $S b H_{3}$ is greater than that of $N H_{3}$ .
The correct order of boiling point of group $15$ hydrides is $P H_{3} < A s H_{3} < N H_{3} < S b H_{3} < B i H_{3}$ .

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Similar questions

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

S i F_{4} < S i C l_{4} < S i B r_{4} < S i I_{4}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > P H_{3} > A s H_{3} > S b H_{3} > B i H_{3}

N H_{3}, P H_{3}, A S H_{3}, S b H_{3}, B i H_{3}

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