Assertion -The electrolysis of acidified water is considered to be an example of catalysis- Reason- An addition of acid like sulphuric acid makes it an electrolyte- In the presence of H- and ions SO-24- water becomes capable of dissociation- Sulphuric acid does not take part in the reaction but promotes the reaction or increases the rate of the reaction-

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Question

Assertion :The electrolysis of acidified water is considered to be an example of catalysis. Reason: An addition of acid like sulphuric acid makes it an electrolyte. In the presence of $H^{+}$ and ions $S O_{4}^{- 2}$ , water becomes capable of dissociation. Sulphuric acid does not take part in the reaction but promotes the reaction or increases the rate of the reaction.

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion.

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Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion.

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Assertion is correct but Reason is incorrect.

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Both Assertion and Reason are incorrect.

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Solution

The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for Assertion.
Pure / distilled water is a non-electrolyte . An addition of acid like sulphuric acid makes it an electrolyte.In the presence of $H^{+}$ and ions $S O_{4}^{- 2}$ ( from $H_{2} S O_{4}$ ), water becomes capable of dissociation.Sulphuric acid doesn't takes part in the reaction but promotes the reaction or increases the rate of the reaction.Therefore, it can be called the catalyst of the reaction and thus the electrolysis of acidulated water is considered to be an example of catalysis.

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Q. Assertion :Pure water, a non-electrolyte becomes an electrolyte on addition of dil.

H_{2} S O_{4}

. Reason: In the presence of

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H_{2} S O_{4}

), water becomes capable of dissociation. Sulphuric acid does not take part in the reaction but promotes the reaction or increases the rate of the reaction.

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Reason (R) A catalyst participating in the reaction forms different activated complex and lowers down the activation energy but the difference in enrgy of reactant and product remains the same.

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