wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Assertion :The first IE of Be is greater than that of B. Reason: 2p-orbital is lower in energy than 2s.

A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Assertion is correct but Reason is incorrect
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Assertion is incorrect but Reason is correct
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C Assertion is correct but Reason is incorrect
The first IE of Be (899 kJ/mol) is greater than that of B (801 kJ/mol).
B has electronic configuration 1s22s22p1. Be has electronic configuration 1s22s2. B has single electron in 2p orbital and Be has pair of electrons in 2s orbital. The removal of a p electron requires less energy than s-electron from same principal quantum shell. Assertion is correct but Reason is incorrect.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Ionization Enthalpy
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon