CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Assertion :The number of terms in the expansion of (x1+x2+......x10)5 are 14C5 Reason: The number of ways of dividing n identical items among r persons, each one of whom, can receive 0,1,2,.....,n items is equal to n+r1Cn

A
Both (A) & (R) are individually true & (R) is correct explanation of (A),
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Both (A) & (R) are individually true but (R) is not the correct (proper) explanation of (A).
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(A)is true but (R) is false,
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(A)is false but (R) is true.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A Both (A) & (R) are individually true & (R) is correct explanation of (A),
We know the number of terms in the expansion of (x1+x2+.....xr)n are n+r1Cr1=n+r1Cn
Now putting n=5,r=10 n+r1Cn=5+101C5=14C5
Hence Assertion is followed by Reason.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Special Integrals - 1
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon