Question

Assertion :The numerical value of Van der Waals constant $a$ for $H_{2}O$ is higher than $C_6{H}_6$. Reason: $H_{2}O$ shows $H$-bonding.

• A. Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
• B. Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
• C. Assertion is correct but Reason is incorrect
• D. Assertion is incorrect but Reason is correct

Answer 1

The correct option is D Assertion is incorrect but Reason is correct

Vander waal constant values of $H_{2}O$ and $C_6{H}_6$ is $5.536L^{2}bar.mo{l}^{-2}$ and $18.24L^{2}bar.mo{l}^{-2}$ respectively.

So the vanderwall constant value benzene is more than the water due to the H-bonding in water.

So the Assertion is incorrect but Reason is correct.

Hence option D is correct.