Assertion :The ratio $\frac{C_{V}}{C_{P}}$ for a monatomic gas is less than for a diatomic gas. Reason: The molecules of a monatomic gas have more degrees of freedom than those of a diatomic gas.

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

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Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

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Assertion is correct but Reason is incorrect

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Assertion is incorrect and Reason is correct

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Solution

The correct option is C Assertion is correct but Reason is incorrect
For monatomic gas,
$f = 3$
$C_{V} = \frac{3 R}{2}$
$C_{P} = \frac{5 R}{2}$ ;
$\frac{C_{V}}{C_{P}} = \frac{3}{5}$
For diatomic gas, $f = 5$
$C_{V} = \frac{5 R}{2}$
$C_{P} = \frac{7 R}{2}$ ;
$\frac{C_{V}}{C_{P}} = \frac{5}{7}$

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Assertion :The ratio CVCP for a monatomic gas is less than for a diatomic gas. Reason: The molecules of a monatomic gas have more degrees of freedom than those of a diatomic gas.

The correct option is C Assertion is correct but Reason is incorrectFor monatomic gas,f=3CV= 3R2CP= 5R2 ; CVCP= 35For diatomic gas, f=5CV= 5R2CP= 7R2 ; CVCP= 57

Assertion :The ratio $\frac{C_{V}}{C_{P}}$ for a monatomic gas is less than for a diatomic gas. Reason: The molecules of a monatomic gas have more degrees of freedom than those of a diatomic gas.

The correct option is C Assertion is correct but Reason is incorrect
For monatomic gas,
$f = 3$
$C_{V} = \frac{3 R}{2}$
$C_{P} = \frac{5 R}{2}$ ;
$\frac{C_{V}}{C_{P}} = \frac{3}{5}$
For diatomic gas, $f = 5$
$C_{V} = \frac{5 R}{2}$
$C_{P} = \frac{7 R}{2}$ ;
$\frac{C_{V}}{C_{P}} = \frac{5}{7}$