Assertion :The value of the determinant ∣∣
∣
∣∣tan−1xcot−1xπ/2sin−1(4/5)sin−1(3/5)sin−11cos−1(3/5)cos−1(4/5)1∣∣
∣
∣∣ is equal to zero for all values of x. Reason: 2cos−1x=cos−1(2x2−1) if −1≤x≤1
A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Assertion is incorrect but Reason is correct
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Solution
The correct option is C Assertion is correct but Reason is incorrect Statement-2 is true if 0≤x≤1 For −1≤x<0,2cos−1x=π−cos−1(2x2−1) so statement-2 is false. If Δ denotes the given determinant Then Δ=∣∣
∣
∣∣tan−1x+cot−1xcot−1xπ/2sin−1(4/5)+sin−1(3/5)sin−1(3/5)sin−11cos−1(3/5)+cos−1(4/5)cos−1(4/5)1∣∣
∣
∣∣ (Applying C1→C1+C2) ∣∣
∣
∣
∣
∣
∣∣π/2cot−1xπ/2sin−1[45√1−925+35√1−1625]sin−1(3/5)sin−11cos−1[35×45−√1−925√1−1625]cos−1(4/5)1∣∣
∣
∣
∣
∣
∣∣ ∣∣
∣
∣∣π/2cot−1xπ/2sin−11sin−1(3/5)sin−11cos−10cos−1(4/5)1∣∣
∣
∣∣=0 (because cos−10=1) (C1 and C2 are identical) So statement-1 is true.