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Question

Assertion :The value of the determinant ∣ ∣ ∣tan1xcot1xπ/2sin1(4/5)sin1(3/5)sin11cos1(3/5)cos1(4/5)1∣ ∣ ∣ is equal to zero for all values of x. Reason: 2cos1x=cos1(2x21) if 1x1

A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Assertion is incorrect but Reason is correct
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Solution

The correct option is C Assertion is correct but Reason is incorrect
Statement-2 is true if 0x1
For 1x<0,2cos1x=πcos1(2x21)
so statement-2 is false.
If Δ denotes the given determinant
Then
Δ=∣ ∣ ∣tan1x+cot1xcot1xπ/2sin1(4/5)+sin1(3/5)sin1(3/5)sin11cos1(3/5)+cos1(4/5)cos1(4/5)1∣ ∣ ∣
(Applying C1C1+C2)
∣ ∣ ∣ ∣ ∣ ∣π/2cot1xπ/2sin1[451925+3511625]sin1(3/5)sin11cos1[35×45192511625]cos1(4/5)1∣ ∣ ∣ ∣ ∣ ∣
∣ ∣ ∣π/2cot1xπ/2sin11sin1(3/5)sin11cos10cos1(4/5)1∣ ∣ ∣=0
(because cos10=1)
(C1 and C2 are identical)
So statement-1 is true.

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