Assertion -Two mutually perpendicular tangents to the parabola x2-6y meet at point -1-32 - Reason- The tangents drawn from any point on directrix to the parabola- are perpendicular to each other-

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Assertion :Tw...

Question

Assertion :Two mutually perpendicular tangents to the parabola $x^{2} = 6 y$ meet at point $(- 1, - \frac{3}{2})$ . Reason: The tangents drawn from any point on directrix to the parabola, are perpendicular to each other.

Both Satement 1 and Satement 2 are correct and Satement 2 is the correct explanation for Satement 1

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Both Satement 1 and Satement 2 are correct but Satement 2 is not the correct explanation for Satement 1

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Satement 1 is correct but Satement 2 is incorrect

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Satement 1 is incorrect, Satement 2 is correct

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Solution

The correct option is A Both Satement 1 and Satement 2 are correct and Satement 2 is the correct explanation for Satement 1
$2 y + 3 = 0$ is equation of directrix of the parabola $x^{2} = 6 y$ . And we know
that perpendicular tangent meet at the directrix of parabola.
Hence both statement are correct.

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Assertion :Two mutually perpendicular tangents to the parabola x2=6y meet at point (−1,−32). Reason: The tangents drawn from any point on directrix to the parabola, are perpendicular to each other.

The correct option is A Both Satement 1 and Satement 2 are correct and Satement 2 is the correct explanation for Satement 12y+3=0 is equation of directrix of the parabola x2=6y. And we know that perpendicular tangent meet at the directrix of parabola.Hence both statement are correct.

Assertion :Two mutually perpendicular tangents to the parabola $x^{2} = 6 y$ meet at point $(- 1, - \frac{3}{2})$ . Reason: The tangents drawn from any point on directrix to the parabola, are perpendicular to each other.