Assertion: We find mid points of a class interval as upper as
$\frac{u p p e r c l a s s l i m i t + l o w e r c l a s s l i m i t}{2}$
Reason: To draw frequency polygons independently without drawing histogram it is required to have class mark.
Which of the following is correct

Both A and R are true and R is the correct explanation of A.

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Both A and R are true and R is not the correct explanation of A.

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A is true and R is false.

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A is false and R is true.

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Solution

The correct option is A Both A and R are true and R is the correct explanation of A.
A: By definition, this is true
R: By definition, this is true
Unless the class mark is obtained, one can’t draw frequency polygon independently.
Hence R is correct explanation of A.

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Similar questions

Assertion: We find midpoints of a class interval with the following formula.
$\frac{u p p e r c l a s s l i m i t + l o w e r c l a s s l i m i t}{2}$

Reason: To draw frequency polygons independently without drawing histogram it is required to have the class mark.

Which of the following is correct?

Q. For drawing a frequency polygon of a continuous frequency distribution, we plot the points whose ordinates are the frequencies of the respective classes and abscissae are respectively
(a) upper limits of the classes
(b) lower limits of the classes
(c) class marks of the classes
(d) upper limits of preceding classes

To draw a frequency polygon, we have to first draw a histogram.

Q. Question 22
For drawing a frequency polygon of a continuous frequency distribution, we plot the points whose ordinates are the frequencies of the respective classes and abcissae are, respectively:

A) Upper limits of the classes
B) Lower limits of the classes
C) Class marks of the classes
D) Upper limits of preceding classes

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Assertion: We find mid points of a class interval as upper as upper class limit+lower class limit2 Reason: To draw frequency polygons independently without drawing histogram it is required to have class mark. Which of the following is correct

The correct option is A Both A and R are true and R is the correct explanation of A.A: By definition, this is true R: By definition, this is true Unless the class mark is obtained, one can’t draw frequency polygon independently. Hence R is correct explanation of A.

Assertion: We find mid points of a class interval as upper as
$\frac{u p p e r c l a s s l i m i t + l o w e r c l a s s l i m i t}{2}$
Reason: To draw frequency polygons independently without drawing histogram it is required to have class mark.
Which of the following is correct

The correct option is A Both A and R are true and R is the correct explanation of A.
A: By definition, this is true
R: By definition, this is true
Unless the class mark is obtained, one can’t draw frequency polygon independently.
Hence R is correct explanation of A.